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suma a patru numere consecutive este11.aflati numerele

Răspuns :

a+a+1+a+2+a+3=11
4a=11-6
4a=5
a=1,25
b=2,25
c=3,25
d=4,25
1 numar= a
2 numar= a+1
3 numar= a+2
4 numar= a+3
a+a+1+a+2+a+3=11
4a+6=11
4a= 11-6
4a=5
a=5/4
a=1,25

al 2-lea numar= a+1= 1,25+1=2,25
al 3-lea numar= a+2=1.25+2=3.25
al 4-lea numar= a+3=1.25+3= 4.25