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Media geometrica a numerelor 2la puterea minus 1 si 3 la puterea minus 1 .


Răspuns :


Media g = √(2`¹•3`¹)=√(½•⅓)=√1/6= √1/√6=1/√6=√6/6
   
[tex]\displaystyle \\ m_g = \sqrt{2^{-1} \times 3^{-1} }= \sqrt{ \frac{1}{2} \times \frac{1}{3} }=\sqrt{ \frac{1}{6}}= \frac{1}{ \sqrt{6} }= \boxed{\frac{\sqrt{6} }{6} }[/tex]