-calculez moli compus; n=m/M---> n=3,32g/166g/mol= 0,02mol
-calculez moli NaOH: C= n,mol/V,l---> 1=n/0,04--> n= 0,04moli
0,02molcompus.......0,04molNaOH
1MOL..........................n=2molNaOH---> .deduc ca compusul are 2 grupe functionale care pot reactiona cu NaOH