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Calculeaza concentratia procentuala a unei solutii care rezulta prin dizolvarea unui amestec de 1 mol CuSO4 *5H2O si 0.5 moli CuSO4 in 20 moli apa.

Daca se , sa se explice pasii :3.


Răspuns :

1. Calculezi md din fiecare solutie:
MCuSO4°5H2O=64+32+16*4+5*18=250g/mol
MCuSO4=160g/mol
MH2O=18g/mol
M5°H2O=90g/mol
nr moli=md1/M =>md1=n*M=1*250=250g
n=md2/M =>md2=n*M=0.5*160=80g
n=mH2O/M =>mH2O=n*M=20*18=360g
mdf=md1+md2=250+80=330g
msf=mdf+mH2O=330+360+90=780g
2. Calculezi Cp:
Cp=mdf/msf*100=330/780*100=42.3%