a+b+c=47- prin segmente se rezolva astfel:
a I-------I-------I--------I--5--I
b I-------I } 47
c I-------I--------I-------I
47 -5 =42 (suma segmentelor egale)
42 : 7 = 6 (un segment) b=6
6 x 3+5=18+5=23 a=23
6 x 3 = 18 c=18
verificare: 23 + 6 +18 = 47
Sper ca te-am ajutat !