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Descompuneti in factori:
a) (2x - 1)x + 4x² - 1 ;
b) ( x - 1)² -3(x - 1) + 2 ;
c) [tex] x^{3n [/tex] - [tex] 5^{2n - 6x^{n} [/tex], n ∈ N


Răspuns :

a) (2x-1)x+ (2x)^2-1^2= (2x-1)x+(2x-1)(2x+1)=(2x-1)(x+2x+1)=(2x-1)(3x+1)