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Determinati cifrele a si b stiind ca media aritmetica a numerelor aabb,aba,ba si b este 625

Răspuns :

(aabb+aba+ba+b):4=625
aabb+aba+ba+b=625*4
aabb+aba+ba+b=2500
1000a+100a+10b+b+100a+10b+a+10b+a+b=2500
1202a+32b=2500
1202*2+32b=2500
2404+32b=2500
32b=2500-2404
32b=96
b=96:32
b=3
proba: (2233+232+32+3):4=(2465+32+3):4=(2497+3):4=2500:4=625