[tex] coc\ \textless \ B=\frac{AB}{BC} = \frac{20}{BC} = \frac{3}{4} [/tex]
BC=[tex] \frac{80}{3} [/tex]
In Δ ABC, m<A=90⇒Th Pitagora BC²=AB²+AC²
AC²=[tex] \frac{6400}{9} -400= \frac{6400-3600}{9} = \frac{2800}{9} [/tex]
AC=[tex] \frac{ 20\sqrt{7} }{3} [/tex]
A triunghiului =[tex] \frac{20*20 \sqrt{7} }{6} = \frac{200 \sqrt{7} }{3} [/tex]
