a)Vcutie=20x20x10=4000 cm³
b)Acutie=2(20+20)×10+2×20×20=800+800=1600 cm²
Acarton=1600 ×110%=1760 cm²
c)
diagonala bazei=20√2
1/2 din diagonala bazei= 20√2/2=10√2
OB=OC=√[(10√2)²+10²]=√(200+100)=10√3
inaltimea triunghiului OBC este si mediana =√[(10√3)²-10²]=10√2
Aria triunghi OBC=20×10√2/2=100√2
Aria triunghi OBC=OB×CM/2=10√3×CM/2=100√2
CM=2×100√2/10√3=200√2/10√3=20√6/3
