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cu exercițiu ăsta mă poate ajuta cineva


Cu Exercițiu Ăsta Mă Poate Ajuta Cineva class=

Răspuns :

a) [(18/5 - 13/10): (5/2- 10/3*3/5+3/4)+57/25] :2/15=
= [( 3610-13/10): (5/2-2+3/4)+57/25]*15/2=
= [23/10: (10/4-8/4+3/4)+57/25]*15/2=
= (23/10*4/5 +57/25)*15/2= (92/50+114/50)*15/2= 206/50*15/2=309/10=


b) {[(11/5-4/5)*10/7*(26/5-36/15)+2/5]:3/7-1/3}:1/2=
={[7/5*10/7*(78/15-36/15)+2/5]*7/3-1/3}*2=
=[ (2*42/15+2/5)*7/3-1/3]*2=[(84/15+6/15)*7/3-1/3]*2=(90/15*7/3-1/3)*2=
= (210/15-5/15)*2=200/15*2= 400/15=80/3

c) {[ 15/4: (7/4*3/2+7/4*9/4)+5/7]:5+20/21}*7/3=
= {[15/4:(21/8+63/16)+5/7]*1/5+20/21}*7/3=
= [15/4:(105/16+5/7)*1/5+20/21]*7/3=
= (15/4:815/112*1/5+20/21)*7/3=( 15/4*112/815*1/5+20/21)*7/3=
=(84/163*1/5+20/21)*7/3=(84/815+20/21)*7/3= (1764+16300)/17115*1/3=
=18064/17115*1/3=18064/51345

d)  dupa ce faci operatiile cu fractiile mai mari, obtii:
6/3+97/11-2/11=2+95/11= 117/11