4x/6+5y/9+3z/8=?
x=(225:5+3·36:4)·3
x=(45+3·9)·3
x=(45+27)·3
x=72·3
x=216
y=(415-7·23-5·40):2
y=(415-161-200):2
y=54:2
y=27
z=[32:(24-16)+36-4·8]·7
z=(32:8+36-32)·7
z=(4+4)·7
z=56
4x/6+5y/9+3z/8=(4·216)/6+(5·27)/9+(3·56)/8=144+15+21=180
2) (5/5)·486+(2/5)·375+375+(2/7)·357=1000-a
486+150+375+102=1000-a
1113=1000-a
a=1000-1113
a=-113
3) inseamna ca fiecare copil a primit aceleasi g de tort
4b+4f=1600g :4
b+f=400
b=f
f+f=400
2f=400
f=400/2=200g
deci o fata a primit 200 g iar un baiat tot 200g