b = numarul baietilor
f = numarul fetelor
Metoda algebrica:
f = 3 × b
(f : 2) : b = 1 rest 5
f : 2 = b + 5 |×2
f = 2×b + 10
2×b + 10 = 3×b
3×b - 2×b = 10
b = 10 (baieti)
f = 3×10 = 30 (fete)
Metoda grafica :
b |---------|---------|
f |---------|---------|---------|---------|---------|---------|
f : 2 = 3 segmente egale
3 segmente egale - 2 segmente egale = 1 segment egal = 5
b = 2 × 5 = 10 (baieti)
f = 6 × 5 = 30 (fete)
