CH3 - CH2 - OH + O2 ⇒ CH3 - COOH + H2O
1 l de vin (1000ml) contine 120 ml etanol
m = V·q = 120ml·0,8g/ml = 96g
n alcool = m/M = 96/46 = 48/23 moli
n acid = n alcool ⇒ teoretic: m acid = 96/23 ·60 = 5760/23 = 250,43 g
practic : m = 70% ·250,43 = 175,3 g