M,CH4= (12gC+4gH)/mol= 16g/mol
in16g metan.......12gC......4gH
100g.............x=.75%.......y=25% x+y=100
R: 75%C si 25%H
M,NH3=(14gN+3gH)/mol= 17g/m0l
in 17gNH3...............14gN........................3gH
100g................x=82,35%............y=17,65% x+y=100
CONTINUA SI COMPARA,LA SFARSIT, H% din toti compusii....