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Aratati ca (52-30√3) totul sub radical =3√3 - 5

Răspuns :

√(52-30√3)=√(52-√2700)=√[52+√(2704-2700)]/2-√[52-√(2704-2700)]/2=
=√(52+√4)/2-√(52-√4)/2=√(52+2)/2-√(52-2)/2=√54/2-√50/2=√27-√25=
=√3²-√5²=3√3-5