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descompuneti in factori x^3+4x^2-3x,dau funda

Răspuns :

x^3+4x^2-3x=
=x
(x^2+4x-3)=
=x(x+2-√7)(x+2+√7)
 
Δ=16+12=28
x₁=(-4+√28)/2=-2+√7
x₂
=(-4-√28)/2=-2-√7