NaOH-hidroxid de sodiu
M(masa moleculara)=
=A Na+A O+A H
=23+16+1
=40 u.a.m.
•40gNaOH....16gO
x g NaOH....100gO
---------------------------
=> x=40•100/16
=4000/16
=250 g NaOH
•1molNaOH....16gO
y moli NaOH...100gO
------------------------------
=>y=100•1/16
=6,25 moli NaOH