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4sin30grade minus 2 cos60grade}ori tg45 grade

Răspuns :

   
[tex]\displaystyle \\ \{4\sin 30^o - 2\cos 60^o\} \times \text{tg } 45^o = \\ \\ = \{4\times \frac{1}{2} - 2\times \frac{1}{2} \} \times 1 = \{ \frac{4}{2} - \frac{2}{2} \} \times 1 = \{2 - 1 \} \times 1 = 1 \times 1 = \boxed{1}[/tex]