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Sa se rezolve in R ecuatia!
a)x^2-3x=7-3x
b)x²+x/√2-1=0


Răspuns :

a) -3 se reduce cu -3 si ramane x²=7 =>x₁=√7 si x₂=-√7. b) rationalizam => x²+√2x/2-1=0 => eliminam numitorul => 2x²+√2x-2=0=> Δ=b²-4ac=> Δ=2+16=18 =>√Δ=3√2 =>x₁=(-√2+3√2)/4=2√2/4=√2/2 si x₂=(-√2-3√2)/4=-4√2/4=-√2