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aflati numerele x,y,z daca sunt invers proportionale cu 4,6,8, iar x+y+z=39

Răspuns :

x=k/4
y=k/6
z=k/8
x+y+z=39
k/4+k/6+k/8=39
6k+4k+3k=936
13k=936
k=72
x=k/4=72/4=18
y=k/6=72/6=12
z=k/8=72/8=9