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Rezolvati urmatoarele inecuatii in multimea Z\N
a) 4x+12>0
b) 3x+6≥0
c) -5x-14<0
d) x+2>0
e) -3x-17<0
f) |-7|•x+14≥0
g) -√3x-√108≤0
h) -8x+11>0
i) -2x+√12<0


Răspuns :

---(echivalent)
a)4x+12>0---4x>-12---x>-12/4---x>-3.
b)3x+6>=0---3x>=-6---x>=-6/3---x>=-2
c)-5x-14<0---  -5x<14---x>14/-5---x>-2Intregi4/5
d)x+2>0---x>-2
e)-3x-17<---  -3x<17--- x>17/-3---x>-5Intregi2/3
f)l-7l=-7 p/u x>=0 si 7 p/u x <0 ---7x+14>=---7x>=-14---x>=-14/7---x>=-2
  -7x>=-14--- x<=-14/-7---x<=2
g)-rad3x<=6rad3---x>=6rad3/-rad3(reducem rad3)=6/-1=-6---x>=-6
h)-8x>11---x<11/8
i)-2x>-2rad3---x<2rad3/-2(simplificam cu 2)=rad3/-1=-rad3---x>-rad3