CaC2 + 2H2O ⇒ HC≡CH + Ca(OH)2
m CaC2 pur = 64% ·200 = 128g n = m/M = 2moli
HC≡CH + HCl ⇒ H2C=CH-Cl
nH2C=CHCl ⇒-[-H2C-CHCl-]n-
teoretic: nC2H2 = nCaC2 = 2moli
practic : n = 80% ·2 = 1,6moli
n clorura de vinil = n C2H2 = 1,6 moli m = 1,6·62,5 = 100g
in reactia de polimerizare,cu randament 100% m monomer = mpolimer
m PVC = 100g