[tex]\displaystyle 2x^2-5x+2=0 \\ a=2,~b=-5,~c=2 \\ \Delta=b^2-4ac=(-5)^2-4 \cdot 2 \cdot 2=25-16=9\ \textgreater \ 0 \\ x_1= \frac{5+ \sqrt{9} }{2 \cdot 2} = \frac{5+3}{4} = \frac{8}{4} =2 \\ x_2= \frac{5- \sqrt{9} }{2 \cdot 2} = \frac{5-3}{4} = \frac{2}{4} = \frac{1}{2} [/tex]
