formula generala a diacidului: HOOC-(CH2)n-COOH
compozitia procentuala: 40,7%C, 5,1%H, 54,2%O,
transform raportl masic in raport molar, stiind n= m/M
n,C:n,H:n,O= 40,7/12 : 5,1/1 : 54,2/16
=3,39 : 5,1 : 3,39
= 1: 1,5: 1
IN diacid, trebuie sa fie 4O,--->C4H6O4
C4H6O4+NaOH---> C4H5O4Na+H2o
M, sare= (4x12gC++5gH+4X16gO+23gNa)/mol=140g/mol
140g sare.......................23gNa
100g....................................m= calculeaza !!!!!!