[tex]8^{x}-10y=(2^{3})^{x}-10y=2^{3x}-10y=0\Rightarrow 2^{3x}=10y[/tex]
[tex]2^{x}-5y=0\Rightarrow2^{x}=5y[/tex]
Impartim cele doua relatii
[tex]\frac{2^{3x}}{2^{x}}=\frac{10y}{5y}\Rightarrow 2^{3x-x}=2^{1}\Rightarrow 2x=1\Rightarrow x=\frac{1}{2}[/tex]
Ne folosim de relatia a doua pentru a afla pe y
[tex]5y=2^{\frac{1}{2}}=\sqrt{2}\Rightarrow y=\frac{5}{\sqrt{2}}=\frac{5\sqrt{2}}{2}[/tex]
