ai greseli in text, "mult" =moli ???; care concentratie, C%????
2mol...............................................1mol
2CH3COOH +Zn---> (CH3COO)2Zn +H2
n=0,4mol............................................0,2mol
m,acid= 0,4mol(2x12gC+4gH+2X16gO)/mol= 24g CH3COOH-> aceasta este masa dizolvata in 400g solutie
c/100=md/ms
c= 24x100/400............................calculeaza !!!