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suma a patru nrbconsecutive pare este 132

Răspuns :

x+x+2+x+4+x+6=132
4x+12=132 |-12
4x=120 |:4
x=30- primul nr.
x+2=30+2=32-al doilea nr.
x+4=30+4=34-al treilea nr.
x+6=30+6=36-al patrulea nr
×+×+2+×+4+×+6=132
4×=132-2-4-6
4×=120
×=120:4
×=30
×+2=32
×+4=34
×+6=36