1)
a+b=86
a:b=2si rest 5 a=2b+5
2b+5+b=86
3a=81
a=27
b=86-27=59
2.
a+b+c=145
b:a=2 si rest 3 a>3
b=2a+3
a+2a+3+c=145
3a+c=142 3a=142-c a=(142-c)/3
deoarece nu avem o relatie intre c si celelalte numere avem mai multe solutii
c={ 1, 4, 7, 10,13,16,19,22,....130}
a={47,46,45,44,43,42,41,40,....4}
b={97,95,93,91,89,87,85,83,....11}