a+b+c=319
a+5=b:3 → b=(a+5)*3
a+5=c:4 → c=(a+5)*4
Inlocuind pe b si c in relatia sumei obtinem:
a+(a+5)*3+(a+5)*4=319 → a+3*a+15+4*a+20=319 → 8*a+35=319 →
→ 8*a=319-35 →
→ 8*a=284 →
→ a=284:8 →
→ a=35,5
b = (a+5)*3 =
= (35,5+5)*3=
= 40,5*3 =
= 121,5
c = (a+5)*4 =
= 40,5*4 =
= 162,0