In,ΔABCdr,cateta,AB,este,opusa,∡de,30°=>este,jumatate,din,ipotenuza
AB=BC/2=>BC=24cm
Cu,t.catetei,aflam,segmentul,BD
AB²=BDxBC
144=BDx24=>BD=144/24=>BD=6cm=>DC=24-6=18cm
Cu,t.inaltimii,aflam,inaltimea,AD
AD²=BDxDC
AD²=6x18
AD²=108
AD=√108
AD=6√3
Cu,t.Pit.aflam,si,cealalta,cateta,pentru,a,afla,perimetrul
AB²+AC²=BC²
AC²=BC²-AB²
AC²=576-144
AC²=432
AC=√432
AC=12√3
P=12+12√3+24=36+12√3
P=12(3+√3)
