👤

cum se rezolva:
[(Xx2-40):(3+20)]x5-16=44


Răspuns :

[(2x-40):23]x5-16=44
[(2x-40):23]x5-60=0
[(2x-40):23]x5=60
60/5=12
deci (2x-40):23=12
12x23=276
deco
2x-40=276
2x=276+40
2x=316
x=316/2=158