1. ΔEp = Ec mgΔh = mv² /2 mv²/2 = 2·9,8·5 = 98J
2. ΔEc = ΔEp mv² /2 = mgh max = 400J h max = (mVo²/2) /(mg) = 400/20
h max = 20m (g = 10 N/kg)
3. - la inaltimea h: E = Ep = mgh Ec = 0
- la baza planului : E =Ec = mv²/2 Ep = 0
ΔEc = ΔEp mv² /2 = mgh v² = 2gh = 100 v = 10m/s
4. asupra cutiei actioneaza F = Gx - Ff = mgsinα - F1 = 5√2 - 1 ≈ 6N
a = F/m = 6m/s²
V² = 2al = 2·6·7 =84 v = 9,2m/s