sin 60°=√3/2
CB/DB=CB/8=√3/2
CB=8√3/2=4√3
cos 60°=1/2
DC/DB=DC/8=1/2
DC=8/2=4
A=4×4√3=16√3 cm²
sau
O intersectia diagonalelor
∡BDC=60°
diagonalele in dreptunghi se intretaie in parti egale ⇒ triunghiul DOC
este echilateral si AO=OC=DC=8/2=4
CB=√(8²-4²)=√(64-16)=√48=4√3
A=4×4√3=16√3 cm²