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ajutor?!! Rezolvati ecuatia in C : (1+i)z=3-i ????!!

Răspuns :

(1+i)z=3-i ⇔ z=[tex] \frac{3-i}{1+i} [/tex] ⇔ [tex]z= \frac{(3-i)(1-i)}{(1+i)(1-i)}= \frac{3-3i-i+ i^{2} }{1- i^{2} } = \frac{3-4i-1}{1-(-1)}= \frac{2-4i}{2}= \frac{2(1-2i)}{2}=1-2i. [/tex]