-calculez masa de oxid de etena pura
p/100= mp/mi; 99/100= m,p/4--> mp=3,96t= 3960kg
M,oxid de etena= 44kg/kmol
M,glicol=62kg/kmol
-ecuatia reactiei
CH2-O-CH2+HOH--> CH2OH-CH2OH
44kg.................................62kg
3960kg...............................m=5580kg daca randamentul e100%; practic se va obtine mai putin
82/100= m/5580-------> m,practica=4575,6 kg ; verifica, te rog, calculele !