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Daca axb=-2/5 si axc=1/3 ,atunci

a) ax(b+c)=
b)ax(b-c)=


Răspuns :

a(b+c)=ab+ac=-2/5+1/3=(-6+5)/15=-1/15
a(b-c)=ab-ac=-2/5-1/3=-11/15
Stim ca:
a*b=-2/5 
a*c=1/3 
 a) a*(b+c)=ab+ac ( deoarece inmultirea e distributiva fata de adunare)=-2/5+1/3= (-6+5)/15=-1/15
b)a*(b-c)=ab-ac ( analog) = -2/5-1/3=(-6-5)/15=-11/15