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Este bine cum am rezolvat?
{1300}d.p{2,7,3,1}=
[1300,x,y,z}d.p{2,7,3,1}=
[tex] \frac{1300}{2} = \frac{x}{7} = \frac{y}{3} = \frac{z}{1} [/tex]
[tex]x= \frac{7}{2}
y= \frac{3}{1300}
z= \frac{1}{1300} [/tex]