b = CxH(2x-2) x = 2x - 2 x = 2 b : C2H2
2CH4 ⇒ C2H2 + 3H2
CH4 + NH3 + 3/2 O2 ⇒ HCN + 3H2O
HC≡CH + HCN ⇒ H2C=CH-CN
nH2C=CH-CN ⇒ -[-H2C-(CN)CH-]n-
b) M e = 53·750 = 39750g/mol
c) %C = 36·100/53 = 67,92% %H = 300/53 = 5,66% %N=1400/53=26,415%
d) m(c) = m(d) n (c) = 318/53 = 6 kmoli ← 6moli b +6moli c ← 12 +6 = 18 moli a V (a) = 18·22,4 = 403,2 moli