6.26 CaC2 + 2H2O ⇒ HC≡CH + Ca(OH)2
HC≡CH + H2O + [O] ⇒ HOOC-COOH
2KMnO4 + H2O ⇒ 2KOH + 2MnO2 + 3[O]
n C2H2 /nKMnO4 = 3/2
nMnO2 = nKMnO4 = 9,28/87 = 0,1066 moli
n C2H2 = (3 ·9,28/87)/2 = 0,16 moli ⇒ nCaC2 pur = 0,16 moli m =10,24g
a) p = 10,24·100/32 = 32%
b) n KMnO4 = 0,1066 moli Vs = n /cM = 0,1066l
6.27 HC≡CH + 2[Cu(NH3)2]Cl ⇒ CuC≡CCu + 2NH4Cl + 2NH3
nC2H2 = nC2Cu2 = 3,04/152 = 0,02 moli
26·0,02 + 28n = 28,52g ⇒⇒ n = 1 mol etena
a) nC2H4 : nC2H2 = 1:0,02 = 5:1
b) p = 28··100/28,52 = 98,176%
c) V C2H4 = 571,2·28/28,52 = 560,785m³ n = 25 kmol m = 700 kg
teoretic: m polimer = m monomer = 700kg
practic : m = 560kg
η = 560··100/700 = 80%
