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Demonstrati ca √3 + √9 < √5 + √7

Răspuns :

ridici la patrat in ambele parti si obtii
3+9+2*[tex] \sqrt{3} * \sqrt{9} =5+7+2* \sqrt{5} * \sqrt{7} \ \textless \ =\ \textgreater \ 12+2 \sqrt{27}=12+2 \sqrt{35} [/tex]
dupa reducere obti
[tex] \sqrt{27}\ \textless \ \sqrt{35} [/tex]
coronita?