[tex]\frac{0,5y}{\frac{4}{9}}=\frac{y+3}{8} \\\\\\ 0,5 \to \frac{\not 5}{\not 10}=\frac{1}{2} \\\\\\ \frac{\frac{1}{2}*y}{\frac{4}{9}}=\frac{y+3}{8} \\\\ \not 8* \frac{1}{\not2}*y=\frac{4}{9}* (y+3) \\\\ 4y^{(9}=\frac{4y}{9}+\frac{12}{9} \\\\ 36y-4y=12 \\\\ 32y=12 \ \ \ |:4 \\\\ 8y=3 \\\\\\ \boxed{y=\frac{3}{8}}[/tex]
