HCl este un acid tare, total ionizat-----> [H⁺]=[HCL]------. >trebuie aflata deci concentratia molara a ultimei solutii
-n sau niu= 3,65g/36,5g/mol= 0,1molHCl
c= n/V----. >c1=0,1mol/0,1l= 1M,deoarece 100ml= 0,1l
-c2=n2/V2
1000ml sol1........1mol acid
1ml..................n= 10⁻³mol=n2
c2= 10⁻³mol/1 litru--> c2=10⁻³M---->[H⁺]=[HCL]=10⁻³mol/l
pH= - lg[H⁺]--->pH=-lg10⁻³=3
