A. CxH2x+2 prin ardere---> xCO2 +(x+1)H2O ori a moli
B. CyH2y+2 prin ardere---> yCO2 +(y+1)H2O ori b moli
n,CO2= 358,4l/22,4l/mol= 16mol
n,H2O= 396g/18g/mol=22mol
a/b= 1/2--> b=2a
ax+by=16........................total moli Co2
a(x+1)+b(y+1)=22............total moli H2O
rezolvand sistemul, rezulta a=2mol si b= 4mol
15/22= (14x+2)/(14y+2)
210y-308x=14
x+2y=8---> x=8-2y--> 826y=2478---> y= 3.......propan
x=2........etan
mai verifica,te rog, calculele !
