NE=(2a+2)-(b-d+e)/2=(2*7+2)-16/2=0 => nu are leg. duble
C7H16
Iz. de pozitie:
1) CH3-CH2-CH2-CH2-CH2-CH3-CH3 n-heptan
Iz de catena:
2) CH3-CH(CH3)-CH2-CH2-CH2-CH3 2-metil hexan
3) CH3-CH2-CH(CH3)-CH2-CH2-CH3 3-metil hexan
4) CH3-C(CH3)2-CH2-CH2-CH3 2.2-dimetil pentan
5) CH3-CH(CH3)-CH(CH3)-CH2-CH3 2.3-dimetil pentan
6) CH3-C(CH3)2-CH(CH3)-CH3 2.2.3-trimetil butan
7) CH3-CH2-C(CH3)2-CH2-CH3 3.3-dimetil pentan
8) CH3-CH(CH3)-CH2-CH(CH3)-CH3 2.4-dimetil pentan