V1=V2; V3=2L---> V1=V2=1L
c1=c2--.>n1=n2
c3=1,6=c1+c2---> c1=c2=0,8mol/l
A.m,NaOH= 0,8molx40g/mol= 32g
B.m,NaNO3= 0,8molx85g/mol=68g
C: c,Na=c,OH=c,NO3=0,8mol/l
D.V1=1,5L
V2=3,5L
V3=5L
c1=0,6M---> n1=V1xc1=o,9mol/l
c2=0,2M---> n2=V2xc2= 0,7mol/l
n3= 1,6mol/l
c3=n3/V3--> c3=1,6/5=0,32mol/l
E. la care din solutii se adauga ????