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calculati cantitatea de energie produsa prin metabolizarea a 1 kg de cartofi ce contin 24,3% amidon in procente masice, stiind ca 1 g de glucoza furnizeaza 15,8 Kj.

Răspuns :

1kg=1000g

0.243*1000=243g amidon

180g.......................162g
nC6H12O6 ---> (C6H10O5)n + nH2O
x=270g.....................243g

1g C6H12O6.................................15.8 Kj
270g..............................................x=4266 Kj