n1 moli 2CH4 ⇒ C2H2 + 3/2 H2
n2 moli CH4 nereactionat
amestecul gazos final contine :
- C2H2 : n1/2 moli
- H2 : 3n1/2 moli
- CH4 : n2 moli
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n final = 2n1 + n2
0,5n1·100 /(2n1+n2) = 20 2,5n1= 2n1 + n2 0,5 n1 = n2
n = 2n1 + 0,5n1 = 2,5n1
% C2H2 = 0,5n1·26·100 /( 13n1 + 1,5n1·2+ 0,5n1·16) = 13n1·100/24n1
%C2H2 = 54,16%
% H2 = 3n1·100/24n1 = 12,5%
% CH4 = 8n1·100/24n1 = 33,33%
b) M = (m1+m2+m3)/(n1+n2+n3) = ( 13n1 + 3n1 + 8n1) /(n1 + 0,5n1 + 1,5n1) = 24n1 / 3n1 = 8g/mol
d = 8/28,9 = 0,276