1) [1,1(6)+1[tex] \frac{1}{4} [/tex] :0,(3)]*(2-4/3)^2=
=[ [tex] \frac{16}{9} [/tex] + [tex] \frac{5}{4} [/tex] : [tex] \frac{3}{9} [/tex] ]* [tex] \frac{4}{9} [/tex]=
=( [tex] \frac{16}{9} [/tex] + [tex] \frac{5}{4} [/tex] * [tex] \frac{9}{3} [/tex] )* [tex] \frac{4}{9} [/tex]=
=( [tex] \frac{16}{9} [/tex] + [tex] \frac{45}{12} [/tex] ) * [tex] \frac{4}{9} [/tex]=
=[tex] \frac{597}{108} [/tex] * [tex] \frac{4}{9} [/tex]=
= [tex] \frac{597}{27} [/tex] * 9=
=597*3=
=1791
