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a3+a19=10 calculati a6+a16

Răspuns :

Orice termen al unei progresii aritmetice poate fi scris ca
[tex]a_{n}=a0+n*r[/tex]
In cazul tau avem
[tex]a_{3}+a_{19}=a_{0}+3r+a_{0}+19r=2a_{0}+22r=10[/tex]
In a doua suma avem
[tex]a_{6}+a_{16}=a_{0}+6r+a_{0}+16r=2a_{0}+22r=10[/tex]