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[tex]2 \frac{1}{3} + 0,25+0,(5)=[/tex]

Răspuns :

[tex]\frac{2x3+1}{3}+\frac{25}{100}+\frac{5}{9}=\frac{7}{3}+\frac{1}{4}+\frac{5}{9}[/tex]. Amplifici la prima cu 12, la a doua cu 9 si la a treia cu 4. => (7*12)/(3*12) + (1*9)/(4*9) + 5*4/9*4 ==> 84/36 + 9/36 + 20/36 => (84+9+20)/36 = 113/36
(2x3+1)/3+25/100+5/9=
7/3+1/4+5/9=
12x7/36+9/36+20/36=
(84+9+20)/36=
113/36